document.write( "Question 1160635: The perimeter of the rhombus is 20dm and one of its longer diagonal is 8dm:calculate the length of its shorter diagonal and its area. \n" ); document.write( "
Algebra.Com's Answer #784013 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The perimeter of the rhombus is 20dm and one of its longer diagonal is 8dm:calculate the length of its shorter diagonal and its area.
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Diagonals of a rhombus are PERPENDICULAR to each other.
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document.write( "As the rhombus' perimeter is 20 dm, each side = \"matrix%281%2C4%2C+20%2F4%2C+%22=%22%2C+5%2C+dm%29\"
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document.write( "A rhombus contains 4 right-triangles.
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document.write( "As the longer diagonal's length is 8 dm, and the diagonals of a rhombus bisect each other then each longer leg/side of each right-triangle = \"matrix%281%2C4%2C+8%2F2%2C+%22=%22%2C+4%2C+dm%29\"
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document.write( "Wee now have 4 right-triangles with 3-4-5 PYTHAG. TRIPLES, which means that each SHORTER side/leg of each right-triangle = 3, thus making the 
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document.write( "With each of the 4 right-triangles having legs of 3 dm and 4 dm, each right-triangle's area = 
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document.write( "As there are 4 right-triangles,  \n" );
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