document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160592>Question 1160592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 8 feet longer than it’s wide. If each side is increased 8 feet, then the area is multiplied by 3. What is the size of the original rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783936 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 8 feet longer than it’s wide. If each side is increased 8 feet, then the area is multiplied by 3. What is the size of the original rectangle?<BR>\n" );
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document.write( "L*W = A (original area)<BR>\n" );
document.write( "W*(W+8) = A<BR>\n" );
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document.write( "(W+8)*(W+16) = 3*W*(W+8)<BR>\n" );
document.write( "W+16 = 3W<BR>\n" );
document.write( "W = 8 ft<BR>\n" );
document.write( "L = 16 ft<BR>\n" );
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document.write( "Orig area = 128 sq feet<BR>\n" );
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document.write( "Increased area = 16*24 = 384 sq ft<BR>\n" );
document.write( " </SPAN>\n" );
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