document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160379>Question 1160379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A first aid treatment for extensive burn calls for a solution which is 5% baking soda. How much ounces of water must be added to 12 ounces of a 15% solution of baking soda so that the new solution will only be 5% baking soda? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783842 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "(1) First, a common sense informal solution....<br><BR>\n" );
document.write( "You want the concentration of the solution to be cut to one-third of the current 15%, to 5%.<br><BR>\n" );
document.write( "Since what you are adding is water (no baking soda), that means the solution you start with needs to be one-third of the final mixture.<br><BR>\n" );
document.write( "So the water you are adding is two-thirds of the final mixture; since that is twice as much as what you started with, the amount of water you need to add is 12*2 = 24 ounces.<br><BR>\n" );
document.write( "(2) A formal algebraic solution, using the standard method....<br><BR>\n" );
document.write( "You are combining 12 ounces of 15% baking soda with x ounces of 0% baking soda (water) to get (12+x) ounces of 5% baking soda:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.15%2812%29%2B0%28x%29+=+.05%2812%2Bx%29 ALIGN=MIDDLE  ALT=\".15%2812%29%2B0%28x%29+=+.05%2812%2Bx%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.8+=+0.6%2B.05x ALIGN=MIDDLE  ALT=\"1.8+=+0.6%2B.05x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.2+=+.05x ALIGN=MIDDLE  ALT=\"1.2+=+.05x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+1.2%2F.05+=+24 ALIGN=MIDDLE  ALT=\"x+=+1.2%2F.05+=+24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "(3) And finally, another method for solving mixture problems like this without formal algebra.  This method is the fastest and easiest, if you understand how to use it.<br><BR>\n" );
document.write( "Think of it this way:<BR>\n" );
document.write( "(a) you are starting at 15% baking soda; by adding water (0% baking soda) you are heading towards 0%; but you stop when you get to 5%<BR>\n" );
document.write( "(b) 5% is 2/3 of the way from 15% to 0%<BR>\n" );
document.write( "(c) therefore, 2/3 of the mixture is what you are adding<br><BR>\n" );
document.write( "So the original 12 ounces of 15% baking soda is 1/3 of the mixture; that means the water you are adding is 2/3 of the mixture, which is 24 ounces.<br><BR>\n" );
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