document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160519>Question 1160519</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You want to get the temperature of your pool up to 80 degrees. There are 30 thousand gallons of water in your pool, but it can hold more water. At this point the temperature of the pool water is 78 degrees. You will be adding <BR>\n" );
document.write( "water that is at a temperature of 90 degrees. How many gallons of 90 degree water do you need to add to bring the pool temperature up to 80 degrees? <BR>\n" );
document.write( "Give your answer to the nearest gallon. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783824 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use units of gallon-deg<BR>\n" );
document.write( "have 30000*78=2,340,000 gal-deg now<BR>\n" );
document.write( "want to have  (30000+x)*80=2,400,000+80x gal-deg<BR>\n" );
document.write( "and the initial amount is increased by 90x gal-deg, where x is the number of gallons of 90 degree water.<BR>\n" );
document.write( "so 2340000+90x=2400000+80x<BR>\n" );
document.write( "10x=60000<BR>\n" );
document.write( "x=6000 gallons\r<BR>\n" );
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document.write( "Another way is that there is a 2 degree deficit for 30K gallons, or 60K deficit of gal-deg<BR>\n" );
document.write( "you are adding water that is a 10 degree surplus over what you want, and 6000 gallons of that is 60K gal-deg. </SPAN>\n" );
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