document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107611>Question 107611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle garden is 7ft more than twice its width. If the perimeter of the garden is 56ft, find the width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78380 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let \"l\" be the length and \"w\" be the width of the rectangle.\r<BR>\n" );
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document.write( "So according to the given data, the perimeter = 56 units\r<BR>\n" );
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document.write( "So, by data:  l = 7 + 2w and w = w\r<BR>\n" );
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document.write( "We know that the perimeter is given by P = 2l + 2w \r<BR>\n" );
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document.write( "So substituting for the values, we get: \r<BR>\n" );
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document.write( "56 = 2(7 + 2w) + 2w \r<BR>\n" );
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document.write( "56 = 14 + 4w + 2w\r<BR>\n" );
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document.write( "56 - 14 = 6w\r<BR>\n" );
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document.write( "42 = 6w\r<BR>\n" );
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document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w+=+42%2F6 ALIGN=MIDDLE  ALT=\"w+=+42%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "==> w = 7 \r<BR>\n" );
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document.write( "by back substitution we get: \r<BR>\n" );
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document.write( "l = 7 + 2w\r<BR>\n" );
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document.write( "l = 7 + 14 \r<BR>\n" );
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document.write( "l = 21\r<BR>\n" );
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document.write( "Thus, the solution\r<BR>\n" );
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document.write( " </SPAN>\n" );
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