document.write( "Question 107603: Find the number of Calories in an orange and in a peach.\r
\n" ); document.write( "\n" ); document.write( "1. An orange has 30 Calories more than a peach.\r
\n" ); document.write( "\n" ); document.write( "2. Thirteen peaches have as many Calories as 7 oranges.
\n" ); document.write( "

Algebra.Com's Answer #78376 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Let's use o for the number of calories in an orange, and p for the number of calories in a peach.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We are given that \"o=p%2B30\" and \"13p+=+7o\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Eq 1) \"o-p-30=0\"\r
\n" ); document.write( "\n" ); document.write( "Eq 2) \"7o+-+13p=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Multiply Eq 1) by -7\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Eq 3) \"-7o%2B7p%2B210=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now add Eq 2) and Eq 3) term by term to eliminate the o term.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-6p%2B210=0\"
\n" ); document.write( "\"6p=210\"
\n" ); document.write( "\"p=35\"
\n" ); document.write( "\"o=35%2B30=65\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"13%2A35=455\"
\n" ); document.write( "\"7%2A65=455\"
\n" ); document.write( "
\n" );