document.write( "Question 1160460: A) If sinA=-1/25 and angle A terminates in quadrant IV, what does tanA equal?\r
\n" ); document.write( "\n" ); document.write( "B) Given tan theta=7/24, and theta terminates in Quadrant III, determine the value of cos theta.\r
\n" ); document.write( "\n" ); document.write( "C) If sin theta= 1/2 and theta terminates in Quadrant II, what is the valuse of csc theta * cot theta?
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Algebra.Com's Answer #783754 by MathLover1(20850)\"\" \"About 
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A)
\n" ); document.write( "If \"sin%28A%29=-1%2F25+\"and angle\"+A\" terminates in quadrant IV, what does \"tan%28A%29\" equal?\r
\n" ); document.write( "\n" ); document.write( "If \"sin%28A%29=-1%2F25+\"\r
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\n" ); document.write( "\n" ); document.write( "since \"sin%28A%29=opposite%2Fhypotenuse\"=>\"opposite=1\" and \"hypotenuse=25\"\r
\n" ); document.write( "\n" ); document.write( "to find \"tan%28A%29\" , we need \"cos%28A%29=adjacent%2Fhypotenuse\" \r
\n" ); document.write( "\n" ); document.write( "and \"adjacent=sqrt%2825%5E2-1%5E2%29=sqrt%28624%29=4sqrt%2839%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28A%29=adjacent%2Fhypotenuse\" \r
\n" ); document.write( "\n" ); document.write( "\"cos%28A%29=4sqrt%2839%29%2F25\"\r
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\n" ); document.write( "\n" ); document.write( "then \"tan%28A%29=sin%28A%29%2Fcos%28A%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan%28A%29=%28-1%2F25%29%2F%284sqrt%2839%29%2F25%29\"......simplify\r
\n" ); document.write( "\n" ); document.write( "\"tan%28A%29=-1%2F%284sqrt%2839%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28A%29=-sqrt%2839%29%2F%284%2A39%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28A%29=-sqrt%2839%29%2F156\" in radians\r
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\n" ); document.write( "\n" ); document.write( "\"A=-2.29241\"°\r
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\n" ); document.write( "\n" ); document.write( "in quadrant IV: \"A=360-2.29241=357.70759\"°\r
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\n" ); document.write( "\n" ); document.write( "B) Given \"tan%28+theta%29=7%2F24\", and\"+theta\" terminates in Quadrant III, determine the value of cos\"+theta\".\r
\n" ); document.write( "\n" ); document.write( "\"tan%28A%29=sin%28A%29%2Fcos%28A%29=opposite%2Fadjacent\"=> \"opposite=7\" and \"adjacent=24\"\r
\n" ); document.write( "\n" ); document.write( "find hypotenuse\r
\n" ); document.write( "\n" ); document.write( "\"hypotenuse=sqrt%287%5E2%2B24%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"hypotenuse=sqrt%28625%29\"\r
\n" ); document.write( "\n" ); document.write( "\"hypotenuse\"\"25\"\r
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\n" ); document.write( "\n" ); document.write( "since \"+theta\" terminates in Quadrant III, \"cos%28A%29\" is negative
\n" ); document.write( "so, \"hypotenuse=-25\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28A%29=24%2F-25\"
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\n" ); document.write( "\"cos%28A%29=-24%2F25\" \r
\n" ); document.write( "\n" ); document.write( "since \"tan%28theta%29+=+7%2F24\", use your calculator to find \"theta+=+16.26\"°
\n" ); document.write( "that's in the first quadrant\r
\n" ); document.write( "\n" ); document.write( "in the third quadrant, the angle is \"180+%2B+16.26\"° = \"196.26\"°\r
\n" ); document.write( "\n" ); document.write( "so,\r
\n" ); document.write( "\n" ); document.write( "\"A=196.26\"°\r
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\n" ); document.write( "\n" ); document.write( "C) \r
\n" ); document.write( "\n" ); document.write( "If \"sin%28theta%29=+1%2F2\" and \"theta\" terminates in Quadrant II, what is the values of \"csc%28theta%29%2Acot%28theta%29\"?\r
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\n" ); document.write( "\n" ); document.write( "in Quadrant II: sin is positive, cos is negative, tanis negative\r
\n" ); document.write( "\n" ); document.write( "\"sin%28A%29=opposite%2Fhypotenuse\"=>\"opposite=1\" and \"hypotenuse=2\"\r
\n" ); document.write( "\n" ); document.write( "and \"adjacent=sqrt%282%5E2-1%5E2%29=sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "then \"cos%28A%29=-sqrt%283%29%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "since \"csc%28theta%29+=hypotenuse%2Fopposite\" we have\r
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\n" ); document.write( "\n" ); document.write( "\"csc%28theta%29+=2%2F1=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29+=+adjacent%2Fopposite\"\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29+=+sqrt%283%29%2F1\"\r
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\n" ); document.write( "\n" ); document.write( "\"cot%28theta%29+=+sqrt%283%29+\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( " \"csc%28theta%29+%2A+cot%28+theta%29=2sqrt%283%29\"\r
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