document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160484>Question 1160484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When angles are complementary the sum of their measures is 90 degrees two complementary angles have measure of 2x - 10 degrees and 3x -10 degrees find the measures of each angle  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783752 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the angles are complementary, then their sum is 90 degrees<BR>\n" );
document.write( "(2x - 10) + (3x - 10) = 90<BR>\n" );
document.write( "simplify to get:<BR>\n" );
document.write( "2x - 10 + 3x - 10 = 90<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "5x - 20 = 90<BR>\n" );
document.write( "add 20 to both sides of the equation to get:<BR>\n" );
document.write( "5x = 110<BR>\n" );
document.write( "solve for x to get:<BR>\n" );
document.write( "x = 110 / 5 = 22 degrees.<BR>\n" );
document.write( "2x - 10 = 44 - 10 = 34 degrees.<BR>\n" );
document.write( "3x - 10 = 66 - 10 = 56 degrees.<BR>\n" );
document.write( "34 + 56 = 90 degrees.<BR>\n" );
document.write( "the angles are 34 and 56 degrees and they are complementary.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );