document.write( "Question 1160483: On a certain hot summer's day, 361 people used the public swimming pool. The daily prices are $ 1.50 for children and $ 2.25 for adults. The receipts for admission totaled $ 632.25. How many children and how many adults swam at the public pool that day? \n" ); document.write( "

Algebra.Com's Answer #783749 by greenestamps(13198) $\"\"$ $\"About$

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\n" ); document.write( "By standard algebra....

\n" ); document.write( "x = # of children
\n" ); document.write( "361-x = # of adults

\n" ); document.write( " $\"1.50%28x%29%2B2.25%28361-x%29+=+632.25\"$

\n" ); document.write( "Solve using basic algebra -- although the decimals make the calculations a bit messy.

\n" ); document.write( "Alternatively -- but it doesn't simplify the solution process, since the numbers aren't \"nice\"....

\n" ); document.write( "361 people all children would make a total of 361(1.50) = 541.50.
\n" ); document.write( "632.25-541.50 = 90.75.
\n" ); document.write( "The difference of $90.75 is because of the additional $0.75 per adult.
\n" ); document.write( "90.75/.75 = 121.
\n" ); document.write( "The number of adults was 121; the number of children was 361-121 = 240.

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