document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160426>Question 1160426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee distributor needs to mix a(n) Ethiopian coffee blend that normally sells for $8.10 per pound with a Breakfast coffee blend that normally sells for $14.30 per pound to create 80 pounds of a coffee that can sell for $12.67 per pound. How many pounds of each kind of coffee should they mix?\r<BR>\n" );
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document.write( "A) Write an equation using the information as it is given above that can be solved to answer the question. Use <BR>\n" );
document.write( "x as your variable to represent the quantity of Ethiopian coffee blend.<BR>\n" );
document.write( "Equation:     \r<BR>\n" );
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document.write( "B) Answer: They must mix <BR>\n" );
document.write( " ?pounds of the Ethiopian Blend <BR>\n" );
document.write( " ?pounds of the Breakfast Blend. <BR>\n" );
document.write( "Round your answers to the nearest whole number of pounds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783702 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( " Ethiopian coffee blend that normally sells for $8.10 per pound . let it be x pounds\r<BR>\n" );
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document.write( "Breakfast coffee blend that normally sells for $14.30 per pound let it be y pounds\r<BR>\n" );
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document.write( " to create 80 pounds of a coffee(x+y)  that can sell for $12.67 per pound.\r<BR>\n" );
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document.write( "Quantity \r<BR>\n" );
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document.write( "x+y=80-----------------------(1)\r<BR>\n" );
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document.write( "8.10x+14.30y = 12.67(x+y)\r<BR>\n" );
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document.write( "8.10x + 14.30y = 12.67x+12.67y<BR>\n" );
document.write( "rearrange.<BR>\n" );
document.write( "4.57x-1.63y=0--------------------(2)\r<BR>\n" );
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document.write( "1.00	x	+	1.00	y	=	80.00			<BR>\n" );
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document.write( "4.57	x	+	-1.630	y	=	0.00	.............2		<BR>\n" );
document.write( "Eliminate 	y								<BR>\n" );
document.write( "multiply (1)by		1.63							<BR>\n" );
document.write( "Multiply (2) by		1.00							<BR>\n" );
document.write( "1.63	x		1.63	y	=	130.40			<BR>\n" );
document.write( "4.57	x		-1.63	y	=	0.00			<BR>\n" );
document.write( "Add the two equations									<BR>\n" );
document.write( "6.20	x				=	130.40			<BR>\n" );
document.write( "/	6.20								<BR>\n" );
document.write( "x	=	21.03							<BR>\n" );
document.write( "plug value of			x	in (1)					<BR>\n" );
document.write( "1.00	x	+	1.00	y	=	80.00			<BR>\n" );
document.write( "21.03		+	1.00	y	=	80.00			<BR>\n" );
document.write( "			1.00	y	=	58.97			<BR>\n" );
document.write( "				y	=	58.97			<BR>\n" );
document.write( "Ans	x	=	21.03						<BR>\n" );
document.write( "	y	=	58.97						<BR>\n" );
document.write( "	21.03		pounds	Ethopian coffee					<BR>\n" );
document.write( "	58.97		pounds	Breakfast coffee					\r<BR>\n" );
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document.write( " </SPAN>\n" );
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