document.write( "Question 1160411: if cos theta = -8/17 and theta is in quadrant 3,
\n" ); document.write( "cos 2theta= ? A.161/289 B.-161/289 C.64/289 D.-62/289
\n" ); document.write( "and tan 2 theta=? A. -30/217 B-30/161 C.-240/217 D.-240/161
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Algebra.Com's Answer #783686 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "if \"cos+%28theta%29+=+-8%2F17\" and theta is in quadrant 3,\r
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\n" ); document.write( "\n" ); document.write( "\"cos+%5E2%28theta%29=+%28-8%2F17%29%5E2=64%2F289+\"\r
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\n" ); document.write( "\n" ); document.write( "answer:\r
\n" ); document.write( "\n" ); document.write( "C.\"64%2F289+\"\r
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\n" ); document.write( "\n" ); document.write( "and \"tan%5E2+%28theta%29=sin%28theta%29%2F+cos+%28theta%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28theta%29=opposite%2Fhypotenuse\"
\n" ); document.write( " \"cos%28theta%29=adjacent%2Fhypotenuse+\"
\n" ); document.write( "\"tan%28theta%29=opposite%2Fadjacent+\"\r
\n" ); document.write( "\n" ); document.write( "if \"cos+%28theta%29+=+-8%2F17\" =>\"adjacent=-8\" and \"hypotenuse=17+\"\r
\n" ); document.write( "\n" ); document.write( "using Pythagorean theorem, we have\r
\n" ); document.write( "\n" ); document.write( "\"opposite=sqrt%2817%5E2-%28-8%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"opposite=sqrt%28289-64%29\"\r
\n" ); document.write( "\n" ); document.write( "\"opposite=sqrt%28225%29\"\r
\n" ); document.write( "\n" ); document.write( "\"opposite=15\"\r
\n" ); document.write( "\n" ); document.write( "and if \"theta\" is in quadrant \"III\", in quadrant \"III\", \"cos%28theta%29+%3C+0\", \"sin%28theta%29+%3C+0\" and \"tan%28theta%29+%3E+0+\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28theta%29=-opposite%2Fhypotenuse\"....substitute opposite and hypotenuse\r
\n" ); document.write( "\n" ); document.write( "\"sin%28theta%29=-15%2F17\"\r
\n" ); document.write( "\n" ); document.write( "then \"tan%28theta%29+=+%28-15%2F17%29%2F+%28-8%2F17%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28theta%29+=+%2815%2Fcross%2817%29%29%2F+%288%2Fcross%2817%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28theta%29+=+15%2F+8+\"\r
\n" ); document.write( "\n" ); document.write( "and
\n" ); document.write( "\"tan%5E2%28theta%29+=+%2815%2F+8+%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%5E2%28theta%29+=+225%2F+64\"\r
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\n" ); document.write( "\n" ); document.write( "then, \r
\n" ); document.write( "\n" ); document.write( "\"tan%282theta%29+=+2tan%28theta%29+%2F+%281+-+tan%5E2%28theta%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%282theta%29+=+2%2815%2F+8+%29+%2F+%281+-+225%2F+64%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%282theta%29+=+%2815%2F+4+%29+%2F+%28%2864+-+225%29%2F+64%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%282theta%29+=+%2815%2F+1+%29+%2F+%28-161%29%2F+16%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%282theta%29+=+-240%2F161\"\r
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\n" ); document.write( "\n" ); document.write( "answer:\r
\n" ); document.write( "\n" ); document.write( "D.\"-240%2F161\"
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