document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160346>Question 1160346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A computer that was purchased for $1,200 is now worth $450. If it is depreciating at a rate of 9% per<BR>\n" );
document.write( "year, how old is the computer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783630 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A computer that was purchased for $1,200 is now worth $450. If it is depreciating at a rate of 9% per<BR>\n" );
document.write( "year, how old is the computer?<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Each year, it's worth 91% of the previous year, = 0.91 times as much.<BR>\n" );
document.write( "450 = 1200*(0.91)^y  ---- y = years<BR>\n" );
document.write( "0.91^y = 450/1200 = 3/8<BR>\n" );
document.write( "---<BR>\n" );
document.write( "y*log(0.91) = log(3/8)<BR>\n" );
document.write( "y = log(0.375)/log(0.91)<BR>\n" );
document.write( "y =~ 10.4 years </SPAN>\n" );
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