document.write( "Question 107572: c=5/9(f-32) need to isolate for f \n" ); document.write( "
Algebra.Com's Answer #78363 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! C=5/9(F-32) \n" ); document.write( "C=(5F-160)/9 NOW CROSS MULTIPLY \n" ); document.write( "5F-160=9C ADD 160 TO BOTH SIDES \n" ); document.write( "5F=9C+160 NOW DIVIDE BY 5 \n" ); document.write( "F=9C/5+32 \n" ); document.write( " \n" ); document.write( " |