document.write( "Question 107572: c=5/9(f-32) need to isolate for f \n" ); document.write( "
Algebra.Com's Answer #78363 by checkley71(8403)\"\" \"About 
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C=5/9(F-32)
\n" ); document.write( "C=(5F-160)/9 NOW CROSS MULTIPLY
\n" ); document.write( "5F-160=9C ADD 160 TO BOTH SIDES
\n" ); document.write( "5F=9C+160 NOW DIVIDE BY 5
\n" ); document.write( "F=9C/5+32
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