document.write( "Question 1160279: A container with base measuring 60cm by 40cm and a height of 25cm was 4/5 filled with water. some of the water was removed, causing the water level to fall by 5 cm. The remaining water was then poured in to a tank and a basin, filling them to their brims, the capacity of basin was 1/3 that of the tank. if the tank was 18cm long and 15 cm wide. what was the height of the water in the tank?? \n" ); document.write( "
Algebra.Com's Answer #783563 by greenestamps(13209)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Depth of container: 25cm

\n" ); document.write( "Depth of water in container originally: (4/5) of 25cm = 20cm

\n" ); document.write( "Depth of water after some was removed: 20-5 = 15cm

\n" ); document.write( "Volume of water remaining: 60*40*15 = 36000 cm^3

\n" ); document.write( "Capacity of tank: (3/4) of 36000 cm^3 = 27000 cm^3 (because the capacities of the tank and basin are in the ratio 3:1)

\n" ); document.write( "Height of tank (volume of tank, divided by cross-sectional area of the tank): 27000/(18*15) = 27000/270 = 100

\n" ); document.write( "ANSWER: the height of the water in the tank = the height of the tank = 100cm.

\n" ); document.write( "
\n" ); document.write( "
\n" );