document.write( "Question 1160244: A taxi company charges a fixed hire fee (which is a whole number of dollars) plus a rate for each
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document.write( "kilometer (which is a multiple of 10¢ and more than the set national minimum rate of $1.75),
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document.write( "rounded up to the nearest kilometer.
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document.write( "Maira’s last journey cost $37.90, but she does not know how far it was, or what the fixed hire fee
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document.write( "is. She wants to know how far the journey was.\r
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document.write( "She has a previous bill from the same taxi company, for a different journey, for $21.80.
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document.write( "How far was her last journey? \n" );
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Algebra.Com's Answer #783555 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A taxi company charges a fixed hire fee (which is a whole number of dollars) plus a rate for each kilometer (which is a multiple of 10¢ and more than the set national minimum rate of $1.75), rounded up to the nearest kilometer. \n" ); document.write( "Therefore min dist: 1.75/.1 = 17.5 ~ 18 km min dist \n" ); document.write( "f(x) = .10x + a \n" ); document.write( "Maira’s last journey cost $37.90, but she does not know how far it was, or what the fixed hire fee is. \n" ); document.write( "x = dist traveled \n" ); document.write( "a = fixed amt \n" ); document.write( ".10x + a = 37.90 \n" ); document.write( "a = -.10x + 37.90 \n" ); document.write( "She wants to know how far the journey was. \n" ); document.write( "She has a previous bill from the same taxi company, for a different journey, for $21.80. \n" ); document.write( "y = dist traveled in this journey \n" ); document.write( ".10y + a = 21.80 \n" ); document.write( "a = -.10y + 21.80 \n" ); document.write( "How far was her last journey \n" ); document.write( ": \n" ); document.write( "Using these two equations \n" ); document.write( ".10x + a = 37.90 \n" ); document.write( ".10y + a = 21.80 \n" ); document.write( "---------------------subtraction eliminates a \n" ); document.write( ".10x - .10y = 16.10 \n" ); document.write( ".10x - .10y = 16.10 \n" ); document.write( "-.10y = -10x + 16.10 \n" ); document.write( "get rid of the neg and decimal mult by -10 \n" ); document.write( "y = x - 161 \n" ); document.write( "lets assume y = 18 km (min trip) \n" ); document.write( "x - 161 = 18 \n" ); document.write( "x = 161 + 18 \n" ); document.write( "x = 179 kms \n" ); document.write( ": \n" ); document.write( "see of that gives us our fixed fee \n" ); document.write( ".10(179) + a = 37.90 \n" ); document.write( "17.90 + a = 37.90 \n" ); document.write( "a = 37.90 - 17.90 \n" ); document.write( "a = $20 is the fixed fee \n" ); document.write( ": \n" ); document.write( "See if that checks out with 2nd trip y = 18 km \n" ); document.write( ".10y + a = 21.80 \n" ); document.write( ".10(18) + a = 21.80 \n" ); document.write( "1.80 + a = 21.80 \n" ); document.write( "a = 21.80 - 1.80 \n" ); document.write( "a = $20 here too \n" ); document.write( ": \n" ); document.write( "Summarizing \n" ); document.write( "fixed fee = $20 \n" ); document.write( "1st trip: 179 km \n" ); document.write( "2nd trip: 18 km \n" ); document.write( " |