document.write( "Question 1159987: Two forces act on an object at 30° to each other. One force has a magnitude of 180 N, and the resultant has a magnitude of 320 N. a) Draw a vector diagram illustrating this situation. \n" ); document.write( "
Algebra.Com's Answer #783471 by KMST(5328)\"\" \"About 
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The magnitude of the resultant of the twp forces, in Newton, is \"R=320\" .The magnitude of a known first force, in Newton, is \"F1=180\" .
\n" ); document.write( "Let the magnitude of the second force be \"F2\" Newton.
\n" ); document.write( "I would draw my vector diagram as shown below.
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\n" ); document.write( "Depending on instructor preferences, the diagram expected could have
\n" ); document.write( "both vectors starting from the same point with parallel segments added forming a parallelogram, like this:
\n" ); document.write( " .
\n" ); document.write( "I could solve it several different ways,
\n" ); document.write( "but here is a simple way, assuming knowing only a little trigonometry.
\n" ); document.write( "We are concerned with two right triangles, \"ABC\" and \"ABD\" below.
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\n" ); document.write( "\"AB=320\" (the magnitude of R)
\n" ); document.write( "\"BC=180\" (the magnitude of F1)
\n" ); document.write( "We want to find \"AC\" (the magnitude of F2).
\n" ); document.write( "From trigonometry, we find that
\n" ); document.write( "\"CD=180%2Acos%2830%5Eo%29=155.88\" and \"BD=180%2Asin%2830%5Eo%29=90\" .
\n" ); document.write( "We can find \"AD\" simply using the Pythagorean theorem as
\n" ); document.write( "In physics class you could say those are the magnitudes of the horizontal and vertical components of F1.
\n" ); document.write( "\"AD=sqrt%28AB%5E2%2BBD%5E2%29=sqrt%28320%5E2-90%5E2%29=307.08\"
\n" ); document.write( "You could say that \"AD+is+the+magnitude+of+the+horizontal+component+of+R.%0D%0AWith+%7B%7B%7BAD\" and \"CD\" , we find
\n" ); document.write( "\"AC=AD-CD=307.08-155.88=151.2\"
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