document.write( "Question 1160202: Find all solutions of the equation on the interval [0,2pi)\r
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document.write( "-4sinx = -cos^2x+4\r
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document.write( "Write answer in terms of pi \n" );
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Algebra.Com's Answer #783442 by ikleyn(52877) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "-4sin(x) = -cos^2(x) + 4\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Replace cos^2(x) by 1 - sin^2(x). You will get\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "-4sin(x) = -(1-sin^2(x)) + 4\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "sin^2(x) + 4sin(x)x + 3 = 0\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Factor\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(sin(x) + 3)*(sin(x) + 1) = 0\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The only real solution is sin(x) = -1, which gives x =\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |