document.write( "Question 107372This question is from textbook Structure and Method
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document.write( ": I am working on charts and this particular question is giving me a hard time:\r
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document.write( "The length of a red rectangle is 15cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72cm. Make a sketch of the rectangles expressing all dimensions in terms of w. Then find the dimensions of each rectangle. \n" );
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Algebra.Com's Answer #78338 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! The length of a red rectangle is 15cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72cm. Make a sketch of the rectangles expressing all dimensions in terms of w. Then find the dimensions of each rectangle. \n" ); document.write( "Larger rectangular; \n" ); document.write( "L=W+15 \n" ); document.write( "W=W \n" ); document.write( "======================== \n" ); document.write( "smaller rectangular; \n" ); document.write( "L=w+15-2 \n" ); document.write( "W=W+5 \n" ); document.write( "2(w+13)+2(w+5)=72 \n" ); document.write( "2w+26+2w+10=72 \n" ); document.write( "4w+36=72 \n" ); document.write( "4w=36 \n" ); document.write( "w=9 \n" ); document.write( "========================= \n" ); document.write( "Now we will plug the nine in for w, lets do the first one; \n" ); document.write( "W=9 \n" ); document.write( "L=W+15 \n" ); document.write( "L=9+15=24 \n" ); document.write( "------------------------ \n" ); document.write( "w=W+5 \n" ); document.write( "w=9+5=14 \n" ); document.write( "l=w+13 \n" ); document.write( "l=9+13=22 \n" ); document.write( "================================= \n" ); document.write( ":) \n" ); document.write( " |