document.write( "Question 1160001: A campground charges $20.00 to camp for one night. They average 56 people each night. A recent survey indicated that for every $1.00 decrease in the nightly price, the number of camping sites rented increases by 7. \r
\n" ); document.write( "\n" ); document.write( "Create a Revenue equation.\r
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\n" ); document.write( "\n" ); document.write( "What price will maximize nightly revenue? Show the steps of your solution.\r
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Algebra.Com's Answer #783317 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
x=number of $ decrease in price and increased number of rentals by 7
\n" ); document.write( "(20-x)(56+7x)=1120+84x-7x^2, which is the revenue function.
\n" ); document.write( "maximum is where x=-b/2a=-84/-14=6
\n" ); document.write( "so revenue is maximized with 56+42=98 rentals paying $20-$6=$14 a night, or $1372.\r
\n" ); document.write( "\n" ); document.write( "the price should be $14 to maximize revenue.\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-10%2C10%2C-50%2C1500%2C-7x%5E2%2B84x%2B1120%29\"
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