document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160049>Question 1160049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Task 21. Two auditors check the accounts of the company. Each randomly selected 8 accounts. It is known that the probability of an erroneous account among company accounts is 0.05. What is the likelihood that: a. each auditor finds at least one erroneous account; b. will at least one erroneous account be detected? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783315 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p(a) finding at least 1 is 1-p(finding 0)=1-0.95^8=0.3366<BR>\n" );
document.write( "That is the same for b.<BR>\n" );
document.write( "They both have to find at least 1, and that is the joint probability of 0.3366^2=0.1133 rounding at end.\r<BR>\n" );
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document.write( "Sixteen accounts are checked randomly. The probability of finding at least 1 is 1-p(finding 0)=1-0.95^16=0.5599\r<BR>\n" );
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document.write( "This makes qualitative sense in that the probability of both finding at least 1 is more restrictive than just one auditor's finding at least 1. </SPAN>\n" );
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