document.write( "Question 1160126: Tara is two years older than Ashley. In 4 years from now, Tara will be twice as old as Ashley was 4 years ago. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #783302 by saw(34)![]() ![]() ![]() You can put this solution on YOUR website! Solution. \n" ); document.write( "Tara is two years older than Ashley \n" ); document.write( "Let Ashley's age be x. \n" ); document.write( "Then Tara's age will be 2+x. \n" ); document.write( "4 years ago \n" ); document.write( "Ashley's age = (x-4) \n" ); document.write( "4 years hence \n" ); document.write( "Tara's age = 4+2+x = 6+x \n" ); document.write( "In 4 years from now,Tara will be twice as old as Ashley was 4 years ago \n" ); document.write( "6+x = 2(x-4) \n" ); document.write( "Multiply parenthesis by 2 \n" ); document.write( "6+x = 2x-8 \n" ); document.write( "Move terms \n" ); document.write( "x-2x = -8-6 \n" ); document.write( "Collect the like terms & calculate the difference \n" ); document.write( "-x = -14 \n" ); document.write( "Change the signs on both sides of the equation \n" ); document.write( "x = 14 \n" ); document.write( "So Ashley's present age is 14 and Tara's is 16 years.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |