document.write( "Question 1160125: A rectangular garden is surrounded by a walk of uniform width. The area of the garden is 180 square yards. If the dimensions of the garden plus the walk are 16 yards by 24 yards (height by base), find the dimensions of the garden. What is the height? \n" ); document.write( "
Algebra.Com's Answer #783276 by mananth(16946)\"\" \"About 
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\n" ); document.write( "A rectangular garden is surrounded by a walk of uniform width.let it be x yards\r
\n" ); document.write( "\n" ); document.write( " The area of the garden is 180 square yards.\r
\n" ); document.write( "\n" ); document.write( "the dimensions of the garden plus the walk are 16 yards by 24 yards \r
\n" ); document.write( "\n" ); document.write( "length of garden = 16-2x
\n" ); document.write( "width of garden = 24-2x
\n" ); document.write( "Area of garden = L * W
\n" ); document.write( "(16-2x)(24-2x) =180
\n" ); document.write( "384-32x-48x+4x^2= 180
\n" ); document.write( "simplify
\n" ); document.write( "4x^2-80x +204=0
\n" ); document.write( "divide by 4
\n" ); document.write( "x^2-20x+51=0
\n" ); document.write( "x^2-17x-3x+51=0
\n" ); document.write( "x(x-17)-3(x-17) =0
\n" ); document.write( "(x-17)(x-3) =0
\n" ); document.write( "x=17 or 3
\n" ); document.write( "x cannot be 17\r
\n" ); document.write( "\n" ); document.write( "so x=3\r
\n" ); document.write( "\n" ); document.write( "Length 16-6= 10
\n" ); document.write( "24-6 =18
\n" ); document.write( "Garden cannot have height . It has length and width.
\n" ); document.write( "Dimensions of garden = 10 & 18 yards
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