document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160050>Question 1160050</A>: <I><SPAN STYLE=\"word-break: break-all;\"> . The U.S. Department of Transportation maintains statistics for mishandled bags per 1,000 airline passengers. In 2005, Jet Blue had 4.06 mishandled bags per 1,000 passengers (extracted from M. Mullins, Out of Place, USA Today, March 24, 2006, p. 10A). What is the probability that in the next 1,000 passengers, Jet Blue will have<BR>\n" );
document.write( "a. no mishandled bags? b. at least one mishandled bag? c. at least two mishandled bags? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783258 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a Poisson with prob proportional to time, count data, and theoretically infinite number.<BR>\n" );
document.write( "lambda=4.06<BR>\n" );
document.write( "a. e^(-4.06)*(4.06)^)/0!=0.0172<BR>\n" );
document.write( "b. At least 1 is 1-P(0)=0.9828<BR>\n" );
document.write( "c. At least 2 mishandled bags is 1-p(0) -p(1), where p(1)=e^(-4.06)*4.06=0.0700<BR>\n" );
document.write( "This is 1-0.0172-0.0700=0.9128 </SPAN>\n" );
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