document.write( "Question 1159985: The square of a number increased by 3 times the number is 28. Find the positive number. \r
\n" ); document.write( "\n" ); document.write( "*I think I'm supposed to start with x^2(x squared)+3(x+1)=28, and then turn it into x^2(x squared)+3x+3=28, but I'm not sure of how to continue(or if this is right), so any help is appreciated.\r
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Algebra.Com's Answer #783153 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The square of a number increased by 3 times the number is 28. Find the positive number. \r
\n" ); document.write( "\n" ); document.write( "*I think I'm supposed to start with x^2(x squared)+3(x+1)=28, and then turn it into x^2(x squared)+3x+3=28, but I'm not sure of how to continue(or if this is right), so any help is appreciated.\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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NO, you're WRONG!
\n" ); document.write( "Where did you get 3(x + 1) from? It says \"3 times the number.\" Isn't that 3x, with x being the number?
\n" ); document.write( "Therefore, shouldn't the equation be: x2 + 3x = 28, which then results in: x2 + 3x - 28 = 0?
\n" ); document.write( "Solve that for x and you'll get 2 values for x. Then, give your answer based on this request: \"Find the positive number.\" \n" ); document.write( "
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