document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1159985>Question 1159985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The square of a number increased by 3 times the number is 28. Find the positive number. \r<BR>\n" );
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document.write( "*I think I'm supposed to start with x^2(x squared)+3(x+1)=28, and then turn it into x^2(x squared)+3x+3=28, but I'm not sure of how to continue(or if this is right), so any help is appreciated.\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783135 by </B><A HREF=/tutors/aboutme.mpl?userid=MowMow><B>MowMow(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MowMow><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MowMow><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = 'the number'<BR>\n" );
document.write( "x^2 is the square of the number <BR>\n" );
document.write( "+3x is three times the number<BR>\n" );
document.write( "So x^2 + 3x = 28<BR>\n" );
document.write( "   x^2 + 3x - 28 = 0<BR>\n" );
document.write( "Factored:<BR>\n" );
document.write( "   (x-4)(x+7) = 0<BR>\n" );
document.write( "    x-4 = 0<BR>\n" );
document.write( "    x = 4<BR>\n" );
document.write( "and (x+7) = 0<BR>\n" );
document.write( "    x + 7 = 0<BR>\n" );
document.write( "    x = -7<BR>\n" );
document.write( "The number could be either 4 or -7 </SPAN>\n" );
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