document.write( "Question 107530: x/3 + y = 3
\n" ); document.write( "x/2 - y/4 = 1
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Algebra.Com's Answer #78312 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
The best way to handle this one, IMHO, is to start by multiplying through to get rid of all those pesky denominators.\r
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\n" ); document.write( "\n" ); document.write( "Eq 1) \"%28x%2F3%29%2By=3\" can be written \"x%2B3y=9\" and\r
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\n" ); document.write( "\n" ); document.write( "Eq 2) \"%28x%2F2%29-%28y%2F4%29+=+1\" can be written \"+2x-y=4\"\r
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\n" ); document.write( "\n" ); document.write( "Next step is to multiply the first equation by -2, resulting in:\r
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\n" ); document.write( "\n" ); document.write( "Eq 3) \"-2x-6y=-18\"\r
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\n" ); document.write( "\n" ); document.write( "And then add the Eq 2) to Eq 3), term by term giving:\r
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\n" ); document.write( "\n" ); document.write( "\"0x-7y=-14\"\r
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\n" ); document.write( "\n" ); document.write( "And then solve for y\r
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\n" ); document.write( "\n" ); document.write( "\"-7y=-14\"
\n" ); document.write( "\"7y=14\"
\n" ); document.write( "\"y=14%2F7\"
\n" ); document.write( "\"y=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"+2x-2=4\"
\n" ); document.write( "\"2x=6\"
\n" ); document.write( "\"x=3\"\r
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\n" ); document.write( "\n" ); document.write( "Plug your values into both equations and do the arithmetic to check your answer.
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