document.write( "Question 1159952: In a certain class, 40 percent sign of students had a B average at midterm. Of these, 50 percent sign ended up with a course grade of B. Of those who did not have a B average at midterm, 40 percent sign ended up with a course grade of B. If one of the students in the class is selected at random and is found to have received a B for the course, what is the probability that the student did not have a B average at midterm?\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #783084 by Boreal(15235) You can put this solution on YOUR website! Start with 100 students\r \n" ); document.write( "\n" ); document.write( "=======B at midterm=====not B at midterm---Total\r \n" ); document.write( "\n" ); document.write( "B for C====20---------------24---------------44 \n" ); document.write( "no B======20--------------36---------------56 \n" ); document.write( "Total======40--------------60--------------100\r \n" ); document.write( "\n" ); document.write( "The probability that given a B (44), the likelihood of not having a B at midterm was 24/44 or 6/11 (54.5%) \n" ); document.write( " |