document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1159526>Question 1159526</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a car manufacturer believes its windscreen wipers will last on average for three years on their cars if driven by a typical driver in the province. Moreover, the manufacturer believes the lifetime of the wipers under such conditions is Normally distributed with a standard deviation of two years. Find the probability that, if on a car driven by a typical driver, a windscreen wiper lasts for a time that is not within 1.2 years of the mean lifetime.\r<BR>\n" );
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document.write( "The probability is: \r<BR>\n" );
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document.write( "I tried to find (|x-3|>1.2) but I keep getting it wrong so I know I'm going wrong somewhere in the steps.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #783082 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=783082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> within 1.2 years of the mean lifetime is within 0.6 sd (1.2/2)<BR>\n" );
document.write( "so want z<-0.6 and z>0.6<BR>\n" );
document.write( "or 1- z (-1.2, 1.2)=1-0.7699=0.2301\r<BR>\n" );
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document.write( "z=(x-mean)/sd<BR>\n" );
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