document.write( "Question 1159943: The probability of x is given below
\n" );
document.write( "X P(x)
\n" );
document.write( "2 .10
\n" );
document.write( "4 .20
\n" );
document.write( "6 .30
\n" );
document.write( "8 .40
\n" );
document.write( "Answer the following questions
\n" );
document.write( "a) What is the probability that x is less than or equal to 4?
\n" );
document.write( "b) What is the probability that x is greater than or equal to 2?
\n" );
document.write( "c) Calculate the expected value
\n" );
document.write( "d) Calculate the variance
\n" );
document.write( "e) Calculate the standard deviation \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #783079 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( "Part a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The answer is 0.3 since we add the P(x) values when x is 4 or smaller, so when x = 2 or x = 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.10+0.20 = 0.30 = 0.3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=========================================================================== \n" ); document.write( "Part b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"x is greater than or equal to 2\" is basically saying \"every x value mentioned in the table\" because x = 2 is the smallest item listed. \n" ); document.write( "Add up all the P(x) values. You should get 1 as the result. With any probability distribution, all the P(x) values must add to 1 to represent 100%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=========================================================================== \n" ); document.write( "Part c)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Make a column of the product of the X and P(X) values \n" ); document.write( "
\n" ); document.write( "Then add up the values in that new third column: 0.2+0.8+1.8+3.2 = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Expected value = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The expected value is another term for the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=========================================================================== \n" ); document.write( "Part d)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Make yet another column. This time we'll represent the X^2*P(X) values \n" ); document.write( "
\n" ); document.write( "Those new values add to: 0.4+3.2+10.8+25.6 = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then we subtract off the square of the mean, or expected value, we got back in part c \n" ); document.write( "40 - (mean)^2 = 40 - 6^2 = 40 - 36 = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The variance is 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=========================================================================== \n" ); document.write( "Part e)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Apply the square root to the variance to get the standard deviation: \n" ); document.write( "standard deviation = sqrt(variance) \n" ); document.write( "standard deviation = sqrt(4) \n" ); document.write( "standard deviation = 2 \n" ); document.write( " \n" ); document.write( " |