document.write( "Question 1159908: Sovle,giving all the solution between oº and 360º.find 2tan^2x+9 sec x-3=0 \n" ); document.write( "
Algebra.Com's Answer #783011 by Alan3354(69443)\"\" \"About 
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between oº and 360º.find 2tan^2x+9 sec x-3=0
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\n" ); document.write( "2tan^2x+9 sec x-3=0
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\n" ); document.write( "Not clear.
\n" ); document.write( "Is it tan^2(x), or tan(2x), or tan(2x+9) ?
\n" ); document.write( "sec(x), or sec(x-3) ?
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