document.write( "Question 1159908: Sovle,giving all the solution between oº and 360º.find 2tan^2x+9 sec x-3=0 \n" ); document.write( "
Algebra.Com's Answer #783011 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! between oº and 360º.find 2tan^2x+9 sec x-3=0 \n" ); document.write( "------- \n" ); document.write( "2tan^2x+9 sec x-3=0 \n" ); document.write( "------- \n" ); document.write( "Not clear. \n" ); document.write( "Is it tan^2(x), or tan(2x), or tan(2x+9) ? \n" ); document.write( "sec(x), or sec(x-3) ? \n" ); document.write( " |