document.write( "Question 15905: Can you help me with this?
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document.write( "An individual has a total of $1000 in 2 banks. The first bank pays 8% interest per year, the second bank pays 10%. If the person receives $86 in interest in the first year, how much money must have been deposited in each bank?
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document.write( "Thank you for you help! \n" );
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Algebra.Com's Answer #7830 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! You need to set up your equation from the problem description as follows:\r \n" ); document.write( "\n" ); document.write( "$x at 8% + $(1000-x) at 10% = $86 Now you solve for x, the amount in the first bank. First change the percents to their decimal equivalents. 8% = 0.08, 10% = 0.1 Now write the algebraic equation.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "$700.00 was deposited in the first bank at 8% interest per annum. \n" ); document.write( "$300.00 was deposited in the second bank at 10% interest per annum.\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "0.08($700.00) + 0.1($300.00) = $56.00 + $30.00 = $86.00 \n" ); document.write( " |