document.write( "Question 15905: Can you help me with this?
\n" ); document.write( "An individual has a total of $1000 in 2 banks. The first bank pays 8% interest per year, the second bank pays 10%. If the person receives $86 in interest in the first year, how much money must have been deposited in each bank?
\n" ); document.write( "Thank you for you help!
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Algebra.Com's Answer #7830 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
You need to set up your equation from the problem description as follows:\r
\n" ); document.write( "\n" ); document.write( "$x at 8% + $(1000-x) at 10% = $86 Now you solve for x, the amount in the first bank. First change the percents to their decimal equivalents. 8% = 0.08, 10% = 0.1 Now write the algebraic equation.\r
\n" ); document.write( "\n" ); document.write( "\"0.08x+%2B+0.1%281000-x%29+=+86\" Simplify and solve for x.
\n" ); document.write( "\"0.08x+%2B+100+-+0.1x+=+86\"
\n" ); document.write( "\"-0.02x+%2B+100+=+86\" Subtract 100 from both sides.
\n" ); document.write( "\"-0.02x+=+-14\" Divide both sides by -0.02
\n" ); document.write( "\"x+=+700\"\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "$700.00 was deposited in the first bank at 8% interest per annum.
\n" ); document.write( "$300.00 was deposited in the second bank at 10% interest per annum.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "0.08($700.00) + 0.1($300.00) = $56.00 + $30.00 = $86.00
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