document.write( "Question 1159865: A TV manufacturer knows that their TV's have a normally distributed lifespan, with a mean of 5.5 years, and standard deviation of 0.8 years.\r
\n" ); document.write( "\n" ); document.write( "If a TV is picked at random, 3% of the time its life will be less than how many years?\r
\n" ); document.write( "\n" ); document.write( "Give your answer to one decimal place.
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Algebra.Com's Answer #782983 by Boreal(15235)\"\" \"About 
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This is the 3rd percentile, where z=-1.88
\n" ); document.write( "z=(x-mean)/sd
\n" ); document.write( "-1.88=(x-5.5)/0.8
\n" ); document.write( "x-5.5=-1.504
\n" ); document.write( "x=3.996 or 4.0 years.
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