document.write( "Question 1159868: Line A is perpendicular to Line B. Determine
\n" ); document.write( "the equation of Line A if it passes through Line B
\n" ); document.write( "at (5, -1), where Line B is represented by the
\n" ); document.write( "equation x + 2y = 3.
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Algebra.Com's Answer #782971 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "First, a solution using elementary methods; you should understand it and be able to solve similar problems by this method.

\n" ); document.write( "(1) Put the equation of B in slope-intercept form \"y+=+mx%2Bb\" to find the slope.
\n" ); document.write( "\"x%2B2y+=+3\"
\n" ); document.write( "\"2y+=+-x%2B3\"
\n" ); document.write( "\"y+=+%28-1%2F2%29x%2B3%2F2\"
\n" ); document.write( "The slope is (-1/2).

\n" ); document.write( "(2) Find the slope of a line perpendicular to B -- it is the negative reciprocal of the slope of B: +(2/1) = 2

\n" ); document.write( "(3) Find the equation of line A knowing it has a slope of 2 and passes through (5,-1).
\n" ); document.write( "\"y+=+mx%2Bb\"
\n" ); document.write( "\"-1+=+2%285%29%2Bb\"
\n" ); document.write( "\"-1+=+10%2Bb\"
\n" ); document.write( "\"b+=+-1-10+=+-11\"
\n" ); document.write( "The equation is \"y+=+2x-11\"

\n" ); document.write( "A graph of the two lines -- B red, A green....

\n" ); document.write( "\"graph%28400%2C400%2C-12%2C12%2C-12%2C12%2C%28-1%2F2%29x%2B3%2F2%2C2x-11%29\"

\n" ); document.write( "Alternatively, a shortcut using ideas about vectors. This is a quick path to the answer you can use if a formal algebraic solution is not required.

\n" ); document.write( "Given line B with equation \"x%2B2y=3\", every line parallel to B will have an equation of the form \"x%2B2y=c\" for some constant c; and every line perpendicular to B will have an equation of the form \"2x-y=c\" for some constant c.

\n" ); document.write( "Without understanding vectors, what you need to see is that the coefficients of x and y have switched places, and one of them has changed signs. In this example, the coefficients 1 and 2 become 2 and -1.

\n" ); document.write( "So the equation of line A is \"2x-y=c\"; and we can determine the constant c knowing that (x,y)=(5,-1) satisfies the equation.

\n" ); document.write( "\"2x-y=c\"
\n" ); document.write( "\"2%285%29-%28-1%29+=+c\"
\n" ); document.write( "\"11+=+c\"

\n" ); document.write( "The equation of A is \"2x-y+=+11\"

\n" ); document.write( "That is a different form of the same equation found earlier, which was \"y+=+2x-11\"

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