document.write( "Question 107484: Solve the inequality 21/15-3x<0 and express the solution as an
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\n" ); document.write( "a. (5, ∞)
\n" ); document.write( "b. (7, ∞)
\n" ); document.write( "c. (–∞,5)
\n" ); document.write( "d. (–∞, 7)
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Algebra.Com's Answer #78286 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
If \"21%2F%2815-3x%29%3C0\"
\n" ); document.write( "then (15-3x)<0 since the numerator is positive.
\n" ); document.write( "\"15-3x%3C0\"
\n" ); document.write( "\"15-3x%2B3x%3C3x\"Add 3x to both sides.
\n" ); document.write( "\"15%3C3x\"
\n" ); document.write( "\"15%2F3%3C3x%2F3\"Divide both sides by 3.
\n" ); document.write( "\"5%3Cx\" or
\n" ); document.write( "\"x%3E5\"
\n" ); document.write( "Check your answer.
\n" ); document.write( "Pick a number greater than 5. Let's pick 10.
\n" ); document.write( "The inequality should hold true since 10>5.
\n" ); document.write( "\"21%2F%2815-3x%29%3C0\"
\n" ); document.write( "\"21%2F%2815-3%2810%29%29%3C0\"
\n" ); document.write( "\"21%2F%2815-30%29%3C0\"
\n" ); document.write( "\"-21%2F15%3C0\"
\n" ); document.write( "True statement. Good answer.
\n" ); document.write( "a. (5, ∞)
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