document.write( "Question 107480: If a piece of real estate purchased for $50,000 in 1998 appreciates at
\n" ); document.write( "the rate of 5% per year, then its value t years after the purchase will
\n" ); document.write( "be f (t) = 50,000(1.05t ) . According to this model, by how much will the
\n" ); document.write( "value of this piece of property increase between the years 2007 and
\n" ); document.write( "2008?
\n" ); document.write( "a. $2500
\n" ); document.write( "b. $3140
\n" ); document.write( "c. $3880
\n" ); document.write( "d. $31,400
\n" ); document.write( "

Algebra.Com's Answer #78283 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
First, a correction.
\n" ); document.write( "If the property appreciates 5% every year, then after the first year,1999.
\n" ); document.write( "F(1)=50000(1.05)
\n" ); document.write( "After the second year, 2000.
\n" ); document.write( "F(2)=F(1)*(1.05)=50000(1.05)(1.05)=\"50000%281.05%29%5E2\"
\n" ); document.write( "The equation should be
\n" ); document.write( "\"F%28t%29=50000%281.05%29%5Et\"
\n" ); document.write( "then
\n" ); document.write( "2007 would be the 9th year and 2008 would be the 10th year.
\n" ); document.write( "\"F%289%29=50000%281.05%29%5E9\" and
\n" ); document.write( "\"F%2810%29=50000%281.05%29%5E10\"
\n" ); document.write( "or
\n" ); document.write( "\"F%289%29=77566\" and
\n" ); document.write( "\"F%2810%29=81445\"
\n" ); document.write( "The difference between the 10th year and the 9th year would then be
\n" ); document.write( "\"F%2810%29-F%289%29=3879\"
\n" ); document.write( "C.3880, close enough.
\n" ); document.write( "If you used the original equation, the house value increases only $2500,
\n" ); document.write( "after the first year but then increases value by $52,500 every year after.
\n" ); document.write( "At the end of the 10th year, the house would be worth $525,000.
\n" ); document.write( "That would be a great profit.
\n" ); document.write( "
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