document.write( "Question 1159758: y=x^2+6x+3 What is the axis of symmetry? x=x= Compute the coordinates of the vertex: (( , )) compute the yy-intercept as a point: (( , )) find the point symmetric to the yy-intercept \n" ); document.write( "
Algebra.Com's Answer #782825 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Put the equation in vertex form: \"y+=+a%28x-h%29%5E2%2Bk\"

\n" ); document.write( "In that form, the vertex is at (h,k), and the axis of symmetry is x=h.

\n" ); document.write( "Complete the square....

\n" ); document.write( "\"x%5E2%2B6x%2B3+=+%28x%5E2%2B6x%2B9%29%2B3-9+=+%28x%2B3%29%5E2-6\"

\n" ); document.write( "This form of the equation tells us that the vertex is at (-3,-6) and the axis of symmetry is x=-3. That can be seen in the graph:

\n" ); document.write( "\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E2%2B6x%2B3%29\"

\n" ); document.write( "For the y-intercept, set x=0 and evaluate. Using the given form of the equation, it is easy to see that the y-intercept is (0,3).

\n" ); document.write( "The y-intercept is 3 units to the right of the axis of symmetry; the point symmetric with the y-intercept will be 3 units to the left of the axis of symmetry, and it will have the same y value as the y-intercept: (-6,3). That is also easily seen in the graph.

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