document.write( "Question 107477: One number is 3 times another. If the sum of their reciprocals
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Algebra.Com's Answer #78282 by jim_thompson5910(35256)\"\" \"About 
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Let x=first number, y=second number\r
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\n" ); document.write( "\n" ); document.write( "Since one number (say the first number) is 3 times the other, then\r
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\n" ); document.write( "\n" ); document.write( "\"x=3y\"\r
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\n" ); document.write( "\n" ); document.write( "Now the statement \"..the sum of their reciprocals
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\n" ); document.write( "\n" ); document.write( "\"1%2Fx%2B1%2Fy=1%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%283y%29%2B1%2Fy=1%2F6\" Now plug in \"x=3y\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%283y%29%2B%281%2Fy%29%283%2F3%29=1%2F6\" Now multiply the second fraction by \"3%2F3\" to get to the common denominator \"3y\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F%283y%29%2B%283%29%2F%283y%29=1%2F6\" Multiply \r
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\n" ); document.write( "\n" ); document.write( "\"%281%2B3%29%2F%283y%29=1%2F6\" Combine the fractions\r
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\n" ); document.write( "\n" ); document.write( "\"4%2F%283y%29=1%2F6\" Combine the numerators\r
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\n" ); document.write( "\n" ); document.write( "\"4=%283y%29%2F6\" Multiply both sides by 3y\r
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\n" ); document.write( "\n" ); document.write( "\"24=3y\" Multiply both sides by 6\r
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\n" ); document.write( "\n" ); document.write( "\"8=y\" Divide both sides by 3 to solve for y\r
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\n" ); document.write( "\n" ); document.write( "So one number is 8\r
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\n" ); document.write( "\n" ); document.write( "Now multiply 8 by 3 to find the first number\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2A8=24\"\r
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\n" ); document.write( "\n" ); document.write( "So another number is 24\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "Remember their reciprocals should add to \"1%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F8%2B1%2F24\" Turn 8 into 1/8 and 24 into 1/24\r
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\n" ); document.write( "\n" ); document.write( "=\"3%2F24%2B1%2F24\" Multiply 1/8 by 3/3\r
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\n" ); document.write( "\n" ); document.write( "=\"4%2F24\" Add the fractions \r
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\n" ); document.write( "\n" ); document.write( "=\"1%2F6\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So our answer is verified\r
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\n" ); document.write( "\n" ); document.write( "note: the previous answer is incorrect. When you check by adding the reciprocal of 3/2 and 9/2 you get \"2%2F3%2B2%2F9=6%2F9%2B2%2F9=8%2F9\" which is not \"1%2F6\"
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