document.write( "Question 1159721: Two joggers set out at the same time from their homes 84 miles apart. They agree to meet at a point somewhere in between in four hours. If the rate of one is 3mph faster than the rate of the other.\r
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Algebra.Com's Answer #782818 by MathTherapy(10556)\"\" \"About 
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\n" ); document.write( "Two joggers set out at the same time from their homes 84 miles apart. They agree to meet at a point somewhere in between in four hours. If the rate of one is 3mph faster than the rate of the other.
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Let speed of slower jogger be S
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document.write( "Then speed of faster jogger = S + 3
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document.write( "We then get the following DISTANCE equation: 4S + 4(S + 3) = 84
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document.write( "4S + 4S + 12 = 84
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document.write( "8S = 72
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document.write( "Speed of slower jogger, or \"highlight_green%28matrix%281%2C6%2C+S%2C+%22=%22%2C+72%2F8%2C+%22=%22%2C+9%2C+mph%29%29\"
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document.write( "You should be able to find the faster jogger's speed. \n" );
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