document.write( "Question 1159721: Two joggers set out at the same time from their homes 84 miles apart. They agree to meet at a point somewhere in between in four hours. If the rate of one is 3mph faster than the rate of the other.\r
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\n" ); document.write( "\n" ); document.write( "what is the rate of each ?
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Algebra.Com's Answer #782788 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"d=84mil\"
\n" ); document.write( "\"t=4h\"\r
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\n" ); document.write( "\n" ); document.write( "Let \"+s+\" = the speed of the slower jogger in \"mil%2Fh\"
\n" ); document.write( "\"+s+%2B+3+\" = the speed of the faster jogger in \"mil%2Fh\"
\n" ); document.write( "Let \"+d+\" = the distance the slower jogger has to run until they meet
\n" ); document.write( "\"+84+-+d+\" = the distance the faster jogger runs\r
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\n" ); document.write( "\n" ); document.write( "Equation for slower jogger:\r
\n" ); document.write( "\n" ); document.write( "(1) \"+d+=+s%2A4+\"\r
\n" ); document.write( "\n" ); document.write( "Equation for faster jogger:\r
\n" ); document.write( "\n" ); document.write( "(2) \"+84+-+d+=+%28+s+%2B+3+%29%2A4+\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute (1) into (2)\r
\n" ); document.write( "\n" ); document.write( " \"+84+-+4s+=+%28+s+%2B+3+%29%2A4+\"
\n" ); document.write( "\"+84+-+4s+=+4s+%2B+12+\"
\n" ); document.write( "\"+84-12+=+8s+\"
\n" ); document.write( " \"+72+=+8s+\"
\n" ); document.write( " \"+s+=+9\"\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "\"+s+%2B+3+=+12+\"\r
\n" ); document.write( "\n" ); document.write( "\"9%28+mil%2Fh%29\" is the speed of the slower jogger
\n" ); document.write( "\"12%28mil%2Fh%29\" is the speed of the faster jogger\r
\n" ); document.write( "\n" ); document.write( "then distance that slower jogger runs to meet faster jogger is \"+d+=+9%2A4+=36mil\" \r
\n" ); document.write( "\n" ); document.write( "\"+84+-+36+=+48+mil\"-> distance faster jogger runs to meet slower jogger\r
\n" ); document.write( "\n" ); document.write( "the sum of distances is \"36mil%2B48mil=84mil\"\r
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