document.write( "Question 1159700: A basketball is thrown toward a hoop, which is 3m above the ground. The height (y, in metres) if the basketball above the ground after t seconds is given by the equation y= -5t^2 + 10t +2\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "A) the shot misses and the ball hits the floor. What was the hang time of the ball (that is, after how many seconds does the ball hit the ground)?\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "b) The player makes the she shot. How much time has passed between the throwing and the scoring\r
\n" );
document.write( "\n" );
document.write( "Be careful when choosing which number is the solution. The ball first reaches a height of 3m as it is traveling upwards. \n" );
document.write( "
Algebra.Com's Answer #782783 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! when it hits the ground -5t^2+10t+2=0 \n" ); document.write( "or 5t^2-10t-2=0 \n" ); document.write( "t=(1/10)(10+/-sqrt(100+40)) \n" ); document.write( "t=(1/10) (10+/-11.83) \n" ); document.write( "=2.183 seconds\r \n" ); document.write( "\n" ); document.write( "The longer time is the solution for the second part, which is when -5t^2+10t+2=3 \n" ); document.write( "or -5t^2+10t-1=0 \n" ); document.write( "or 5t^2-10t+1=0 \n" ); document.write( "or t=(1/10)(10+/- sqrt(100-20)) \n" ); document.write( "the solutions are 0.106 seconds (going up) and 1.894 sec (going through rim)\r \n" ); document.write( "\n" ); document.write( " |