document.write( "Question 1159720: If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction becomes 1. \n" ); document.write( "
Algebra.Com's Answer #782776 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "A solution using logical reasoning and a bit of trial and error with simple arithmetic....

\n" ); document.write( "When the denominator is decreased by 7, the fraction becomes 1. That means the denominator is 7 more than the numerator. So the fraction is of the form \"n%2F%28n%2B7%29\".

\n" ); document.write( "When the numerator is increased by 3, the fraction becomes (equivalent to) 3/4. So the fraction \"%28n%2B3%29%2F%28n%2B7%29\" is equivalent to 3/4.

\n" ); document.write( "From there you can solve the problem algebraically:

\n" ); document.write( "\"%28n%2B3%29%2F%28n%2B7%29+=+3%2F4\"
\n" ); document.write( "\"3%28n%2B7%29+=+4%28n%2B3%29\"
\n" ); document.write( "\"3n%2B21+=+4n%2B12\"
\n" ); document.write( "\"n+=+9\"

\n" ); document.write( "The original fraction is \"n%2F%28n%2B7%29+=+9%2F16\"

\n" ); document.write( "If you have excellent number sense, you can also work the last part of the problem informally. You know the fraction \"%28n%2B3%29%2F%28n%2B7%29\" is equivalent to 3/4. In the fraction 3/4, the difference between numerator and denominator is 1; you want the difference to be 4 (the difference between n+3 and n+7).

\n" ); document.write( "So the fraction after you increase the numerator by 3 is \"%283%2A4%29%2F%284%2A4%29+=+12%2F16\"; and that makes the original fraction 9/16.

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