document.write( "Question 1159695: √(x + 4) > 2 + √x \n" ); document.write( "
Algebra.Com's Answer #782740 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\ 2\ +\ \sqrt{x}\">\r
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\n" ); document.write( "\n" ); document.write( "Square both sides:\r
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\n" ); document.write( "\n" ); document.write( "\ 4\ +\ 4\sqrt{x}\ +\ x\">\r
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\n" ); document.write( "\n" ); document.write( "Add to both sides:\r
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\n" ); document.write( "\n" ); document.write( "\ 4\sqrt{x}\">\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by \r
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\n" ); document.write( "\n" ); document.write( "\ \sqrt{x}\">\r
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\n" ); document.write( "\n" ); document.write( "Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\ x\">\r
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\n" ); document.write( "\n" ); document.write( "Which is to say:\r
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\n" ); document.write( "\n" ); document.write( "However, this result must be discarded because the most restrictive domain is the domain of the right-hand side expression, namely\r
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\n" ); document.write( "\n" ); document.write( "\,0\">\r
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\n" ); document.write( "\n" ); document.write( "Therefore the solution set is the null set over the reals.
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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