document.write( "Question 1159695: √(x + 4) > 2 + √x \n" ); document.write( "

Algebra.Com's Answer #782737 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"sqrt%28x+%2B+4%29+%3E+2+%2B+sqrt%28x%29\"$ ........square both sides\r
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\n" ); document.write( "\n" ); document.write( " $\"x+%2B+4+%3E+%282+%2B+sqrt%28x%29%29%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+%2B+4+%3E+4+%2B+4sqrt%28x%29%2Bx\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"cross%28x%29+%2B+cross%284%29+%3E+cross%284%29+%2B+4sqrt%28x%29%2Bcross%28x%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"0+%3E+4sqrt%28x%29\"$ \r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( " $\"4sqrt%28x%29%3C0\"$ -> since $\"4%3E0\"$ , inequality will be true only if $\"sqrt%28x%29%3C0\"$ \r
\n" ); document.write( "\n" ); document.write( "=> so, no solution exist because $\"sqrt%28x%29%3E=0\"$ for all real numbers\r
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