document.write( "Question 1159666: Use the given conditions to find the exact value of the expression.
\n" ); document.write( "sin α = − 5/13, tan α > 0, sin (α − 5π/3)\r
\n" ); document.write( "\n" ); document.write( "I got 5+\"sqrt%283%29\"/3 which is wrong. \r
\n" ); document.write( "\n" ); document.write( "This is my work:
\n" ); document.write( "cos a=-\"sqrt%281-sin%5E2+%28theta%29%29\"= 12/13\r
\n" ); document.write( "\n" ); document.write( "b= -5pi/3 which is has the values (-1/2) for cosb and (\"sqrt%283%29\"/2 for sinb.
\n" ); document.write( "I use sin(a-b) formula= sinAcosB+cosAsinB
\n" ); document.write( "= (-5/13)(-1/2)+(12/13)(\"sqrt%283%29\"/2)= 5+12\"sqrt%283%29\"/36 = 5+\"sqrt%283%29\"/3 or am I not suppose to simplify the 12 and 36? \r
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Algebra.Com's Answer #782731 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Use the given conditions to find the exact value of the expression.
\n" ); document.write( "\"sin+%28alpha%29+=+-5%2F13\"
\n" ); document.write( "\"tan+%28alpha%29+%3E+0+\"
\n" ); document.write( "\"sin+%28alpha+-+5pi%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28alpha%29=-sqrt%281-sin%5E2%28alpha%29+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28alpha%29=-sqrt%281-%28-5%2F13%29%5E2+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28alpha%29=-sqrt%281-25%2F169+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28alpha%29=-sqrt%28169%2F169-25%2F169+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28alpha%29=-sqrt%28144%2F169+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28alpha%29=-12%2F13\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan+%28alpha%29+=+%28-5%2F13+%29%2F%28-12%2F13%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"+tan+%28alpha%29+=+5%2F12\"=>\"tan+%28alpha%29+%3E+0+\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin+%28alpha+-+5pi%2F3%29\"->use\r
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\n" ); document.write( "\n" ); document.write( "\"sin+%28alpha+-+beta%29=sin%28alpha%29+cos%28beta%29+-+cos%28alpha%29sin%28beta%29+\"\r
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\n" ); document.write( "\n" ); document.write( "let \"beta=5pi%2F3\", already given \"sin+%28alpha%29+=+-5%2F13+\", and \"cos%28alpha%29=-12%2F13\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin+%28alpha+-+5pi%2F3%29=-%285%2F13%29cos%285pi%2F3%29+-+%28-12%2F13%29+sin%285pi%2F3%29\"....\"cos%285pi%2F3%29=1%2F2\", \"sin%285pi%2F3%29=-sqrt%283%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sin+%28alpha+-+5pi%2F3%29=-5%2F26+-%286sqrt%283%29%29%2F13\"\r
\n" ); document.write( "\n" ); document.write( "\"sin+%28alpha+-+5pi%2F3%29=-5%2F26+-%286sqrt%283%29%29%2F13\"\r
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