document.write( "Question 1159666: Use the given conditions to find the exact value of the expression.
\n" ); document.write( "sin α = − 5/13, tan α > 0, sin (α − 5π/3)\r
\n" ); document.write( "\n" ); document.write( "I got 5+\"sqrt%283%29\"/3 which is wrong. \r
\n" ); document.write( "\n" ); document.write( "This is my work:
\n" ); document.write( "cos a=-\"sqrt%281-sin%5E2+%28theta%29%29\"= 12/13\r
\n" ); document.write( "\n" ); document.write( "b= -5pi/3 which is has the values (-1/2) for cosb and (\"sqrt%283%29\"/2 for sinb.
\n" ); document.write( "I use sin(a-b) formula= sinAcosB+cosAsinB
\n" ); document.write( "= (-5/13)(-1/2)+(12/13)(\"sqrt%283%29\"/2)= 5+12\"sqrt%283%29\"/36 = 5+\"sqrt%283%29\"/3 or am I not suppose to simplify the 12 and 36? \r
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Algebra.Com's Answer #782730 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "In this site, there is a group of lessons, where you can find solutions to many similar problems\r
\n" ); document.write( "\n" ); document.write( "    - Calculating trigonometric functions of angles\r
\n" ); document.write( "\n" ); document.write( "    - Advanced problems on calculating trigonometric functions of angles\r
\n" ); document.write( "\n" ); document.write( "    - Evaluating trigonometric expressions \r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic  \"Trigonometry: Solved problems\". \r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II
\n" ); document.write( "https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "There is nothing EXTRAORDINARY with such problems . . . \r
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\n" ); document.write( "\n" ); document.write( "You simply should know the technique of their solutions, and you can learn this technique from the referred lessons.\r
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