document.write( "Question 1159638: The line y=2x+c is a tangent to the curve y=2x^2-6x+20.find the value of c \n" ); document.write( "
Algebra.Com's Answer #782676 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "\"f%28x%29+=+2x%5E2-6x%2B20+\"\r
\n" ); document.write( "\n" ); document.write( "f'(x) = \"+4x-6+\"\r
\n" ); document.write( "\n" ); document.write( "For the tangent \"+2x%2Bc+\" to just touch f(x), we need to find where f(x) has slope equal to 2:\r
\n" ); document.write( "\n" ); document.write( " 4x-6 = 2 <<< remember, the ENTIRE LHS is the slope of f(x)
\n" ); document.write( " x = 2 \r
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\n" ); document.write( "\n" ); document.write( "At x=2: f(2) = \"2%2A%282%5E2%29+-+6%282%29+%2B+20+=+8-12%2B20+=+16+\"\r
\n" ); document.write( "\n" ); document.write( "So the tangent line \"+2x%2Bc+\" just meets f(x) at x=2, hence it has value 16 there:\r
\n" ); document.write( "\n" ); document.write( " 2x + c = 2(2) + c = 16 ==> c = 12\r
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\n" ); document.write( "\n" ); document.write( "Ans: \"+highlight%28c+=+12%29+\" and the tangent line is y=2x+12, and the point of tangency is (2,16).
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