document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107476>Question 107476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph the following line?  Through (-4,-1) with m=3. So far I have gotten- Y-y1=m(X-x1) Y--1=3(X--4)  Y+1=3x+12  -3x+y=12-1  -3x+y=11  y=3x+11. This is where I get stuck. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78263 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78263\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I graph the following line? Through (-4,-1) with m=3. <BR>\n" );
document.write( "y-3 = m(x+4)<BR>\n" );
document.write( "y = 3(x+4)+3<BR>\n" );
document.write( "y = 3x+12 + 3<BR>\n" );
document.write( "y = 3x + 15<BR>\n" );
document.write( "==========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );