document.write( "Question 1159578: dick sets out on a hike. after walking for a while at 5 miles per hour, he discovers he has forgotten his lunch. a passing truck takes him home at 20 miles per hour. when he gets home he finds that he has lost exactly 1 hour. how far had he walked? \n" ); document.write( "
Algebra.Com's Answer #782621 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! distance is speed * time=5 mph *x =20 mph (1-x), since the two times add up to 1 hour\r \n" ); document.write( "\n" ); document.write( "5x=20-20x \n" ); document.write( "25x=20 \n" ); document.write( "x=0.8 hours which at 5 mph is 4 miles\r \n" ); document.write( "\n" ); document.write( "trip back takes 0.2 hours which at 20 mph is 4 miles.\r \n" ); document.write( "\n" ); document.write( "He walked 4 miles \n" ); document.write( " |