document.write( "Question 1159453: At a uniform rate of 4 drops per section, water is dripping from a faucet. Assuming acceleration of each drop to be 9.81 m/s² and no air resistance, find the distance between two successive drops in mm if the upper drop has been in motion for 3/8 seconds. \n" ); document.write( "
Algebra.Com's Answer #782530 by ikleyn(52832)\"\" \"About 
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document.write( "The time interval between any two successive drops is \"1%2F4\" of a second.\r\n" );
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document.write( "When the upper drop is  \"3%2F8\"  seconds in motion,  the lover drop is  \"3%2F8+%2B+1%2F4\" = \"5%2F8\" seconds in motion.\r\n" );
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document.write( "Now use the formula  h = \"%28g%2At%5E2%29%2F2\"  for the distance of the free falling body and find the distance between the drops as\r\n" );
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document.write( "    distance between = \"%289.81%2A%285%2F8%29%5E2%29%2F2\" - \"%289.81%2A%283%2F8%29%5E2%29%2F2\".\r\n" );
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document.write( "Complete your calculations on your own.\r\n" );
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