document.write( "Question 107383: hi I'm having a problem solving an augmented matrix if someone could help me that would be great!!\r
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document.write( "The directions are solve the system using an augmented matrix\r
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document.write( "5x+2y=2
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document.write( "3x-y=-12\r
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document.write( "Thank-you so much for your help \n" );
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Algebra.Com's Answer #78246 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! Start with the given system\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5x+2y=2 \n" ); document.write( "3x-y=-12\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now write the coefficients and the right side in an augmented matrix:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply Row 1 by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Add -3*Row 1 to Row 2 to get the new Row 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply Row 2 by \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Add -2/5*Row 2 to Row 1 to get the new Row 1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The matrix is now in reduced row echelon form\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So our answer is (-2,6) or \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help with row reduction, check out the Linear Algebra Toolkit \n" ); document.write( " |